WT747 — Flight status: Sioux Lookout

WT WT747

Sioux Lookout — Sandy Lake

Sioux Lookout Airport (YXL)		Sandy Lake Airport (ZSJ)
Usual departure time		Usual arrival time
16:50		17:55

Operating days: Tue. Usual times and days are based on observations in 2020. The schedule may have changed.

Flight status WT747

Flight WT WT747 (Sioux Lookout — Sandy Lake) running from the airport Sioux Lookout Airport (YXL), to the airport Sandy Lake Airport (ZSJ). The flight is operated by the family's aircraft Beech 1900D Airliner. Flight distance is 343 km / 185 miles, and the average flight length is 0 h. 30 min..

Common questions about flight WT747

What time does flight WT747 depart?

Scheduled departure is 16:50 and arrival 17:55, local time at each airport. Operating days: Tue.

How long does flight WT747 take?

On average 30 min. The airports are 343 km / 185 miles apart.

Which aircraft operates flight WT747?

The flight is operated by the family's aircraft Beech 1900D Airliner.

Low Price Calendar Sioux Lookout — Sandy Lake

Types of aircraft flying WT747 WT: Sioux Lookout — Sandy Lake

Beech 1900D Airliner

100%

This section contains information about the types of aircraft and flight numbers that perform the flight. Based on observations in 2020.

Other flights on the route Sioux Lookout — Sandy Lake

	Flight No.	Departure time*	Arrival time*	Aircraft
	WT918	08:15	09:20	Beech 1900D Airliner

* Local time

All data is taken from open sources. The administration of the portal is not responsible for the accuracy of the information. For exact flight information, see the airline's website or the airport's website.